On reviewing "The Edge of Evolution" again, I realized I had gotten Behe's argument wrong, he does require simultaneous mutations, since he is considering a set of two mutations, where a single mutation in the set is deleterious. Apologies, especially to rogue06.
But I do wonder in the case of chloroquine resistance, whether each of the two required mutations is deleterious by itself. I think not, since the probability of both mutations is the multiplied probability of one mutation singly.
Blessings,
Lee
But I do wonder in the case of chloroquine resistance, whether each of the two required mutations is deleterious by itself. I think not, since the probability of both mutations is the multiplied probability of one mutation singly.
Blessings,
Lee
Comment